Question

If sin²y + cosxy = K³ find. What is the value of at x = 1, y = π/4.​

Answer 1

Answer:

sin

2

Y+cosXY=K

Differentiating w.e.r. x, we get

2siny.cosy

dx

dy

+(−sinXY)(x.

dx

dy

+y)=0

dx

dy

=

(sin2y−xsinxy)

ysinxy

⇒

dx

dy

]

x=1,y=

4

π

=

sin

4

π

−sin

4

π

4

π

.sin

4

π

=

1−

2

1

4

π

.

2

1

=

4(

2

−2)

π

Step-by-step explanation:

plz mark me in brainliest answer

Answer 2

Answer:

Hello good morning

Make me the Branlist please buddy

Step-by-step explanation:

sin2Y+cosXY=K

Differentiating w.e.r. x, we get

2siny.cosydxdy+(−sinXY)(x.dxdy+y)=0

dxdy=(sin2y−xsinxy)ysinxy

⇒dxdy]x=1,y=4π=sin4π−sin4π4π.sin4π=1−214π.21=4(2−2)π