if sin3/5 then find the value of cos
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Given,
sin = 3/5
let,
sin = opposite side/Hypotenuse = 3/5
AC = 5, BC = 3, AB = ?
Now,
According to PHYTHAGAROUS THEROM,
(Hypotenuse)² = (side)² + (side)²
(AC)² = (AB)²+(BC)²
(5)² = (AB)² + (3)²
25 = (AB)² + 9
25 - 9 = (AB)²
16 = (AB)²
√16 = AB
√4×4 = AB
4 = AB
:. AB = 4 units.
Now consider,
cos = adjacent side/hypotenuse = AB/AC = 4/5.
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