If sin3 θ =cos(θ-6), find the Value of θ
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We have,
sin3 θ =cos(θ-6)
cos(90-3θ)=cos(θ-6)
90-3θ=θ-6
90+6=θ+3θ
96=4θ
θ=96/4
θ=24
sin3 θ =cos(θ-6)
cos(90-3θ)=cos(θ-6)
90-3θ=θ-6
90+6=θ+3θ
96=4θ
θ=96/4
θ=24
Anonymous:
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