Question

If sin3????=cos(θ-6°), where 3???? and ????-6° are acute angles, find the value of ????.

Answer 1

Step-by-step explanation:

Sin3@=cos(@-6)

[using sin@=cos(90-@)]

cos(90-3@)=cos(@-6)

90-3@=@-6

90+6=@+3@

96=4@

@=96/4

@=24