Math, asked by swanny, 1 year ago

If sin3 theta = cos (theta-6°) and 3 theta and (theta-6°) are acute angles, find theta.

Answers

Answered by Anonymous
328
sin3@=cos(@-6)

[using sin@=cos(90-@)]

cos(90-3@)=cos(@-6)

90-3@=@-6

90+6=@+3@

96=4@

@=96/4

@=24

Answered by abhi569
289
sin 3Ф = cos ( Ф - 6)

sin 3
Ф = sin ( 90 - Ф + 6)  [we know, sin(90 - Ф) = cos Ф

 3Ф = 90 + 6 - Ф

3Ф + Ф = 96 

4Ф = 96 

Ф = 96/4 

Ф = 24 


i hope this will help you

(-:

abhi569: thanks for choosing a brainlist answer
abhi569: (-:
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