If sin3 theta = cos (theta-6°) and 3 theta and (theta-6°) are acute angles, find theta.
Answers
Answered by
328
sin3@=cos(@-6)
[using sin@=cos(90-@)]
cos(90-3@)=cos(@-6)
90-3@=@-6
90+6=@+3@
96=4@
@=96/4
@=24
[using sin@=cos(90-@)]
cos(90-3@)=cos(@-6)
90-3@=@-6
90+6=@+3@
96=4@
@=96/4
@=24
Answered by
289
sin 3Ф = cos ( Ф - 6)
sin 3Ф = sin ( 90 - Ф + 6) [we know, sin(90 - Ф) = cos Ф
3Ф = 90 + 6 - Ф
3Ф + Ф = 96
4Ф = 96
Ф = 96/4
Ф = 24
i hope this will help you
(-:
sin 3Ф = sin ( 90 - Ф + 6) [we know, sin(90 - Ф) = cos Ф
3Ф = 90 + 6 - Ф
3Ф + Ф = 96
4Ф = 96
Ф = 96/4
Ф = 24
i hope this will help you
(-:
abhi569:
thanks for choosing a brainlist answer
Similar questions