if sin30 = cos (A-6) where 3A and (A-6) are both acute angles , then find the value of A
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sin ( 3A ) = cos ( A-6 )
cos ( 90-3A ) = cos ( A-6 )
So, 90-3A = A-6
A = 24 DEGREES
amaira1410:
answer is 24
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