Question

If sin30º = k and cos x =1-2k²;a, Bare the value of x between 0 and 360° with a <B, then
(a) a + B = 180° (b) B-a = 200° (C) B = 4a +60° (d) B = 5a -20°​

Answer 1

If sin 3A = cos (A-26°), where 3A is an acute angle, find the

value of A.

Given that,

sin 3A = cos (A-26")

cos (90-3A) = cos (A - 26")

Comparing angles

90-3A A-26°

-3A-A=-26-90

-4A=-116

A=

-116

A = 29

Hence, A = 29"

(sin cos (90-0))

Answer 2

Answer:

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