Question

If sin330 = k , then find cos570 and tan570​

Answer 1

Answer:

$sin \: 330 = k \\ sin(360 - 30) = k \\ - sin \: 30 = k \\ k = - \frac{1}{2}$

$cos \: 570 = cos(360 + 210) \\ = cos \: 210 \\ = cos \: (270 - 60) \\ = - sin \: 60 \\ = - \ \frac{ \sqrt{3} }{2}$

$tan \: 570 = tan(360 + 210) \\ = tan \: 210 \\ = tan(270 - 60) \\ = cot \: 60 \\ = \frac{1}{ \sqrt{3} }$

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