Math, asked by rubidheena03, 1 year ago

if sin3a=cos(a-20),where 3a and (a-20) are both acute angles,then find a=?

Answers

Answered by manasubdarsujay
0

Answer:

Step-by-step explanation:

cos(90-3a)=cos(a-20)

90+20=a+3a

110=4a

a=27.75

I think its this


rubidheena03: how do i know
rubidheena03: they gave me the answer but not the steps
rubidheena03: so i am asking u how to do
gargnakul67: 23 answer is the wrong
gargnakul67: I have checked many times
gargnakul67: Found answer 23.5
rubidheena03: if u don't want to share then it's ok
rubidheena03: i think i found answer
rubidheena03: tks for ur help
Answered by gargnakul67
1

Answer:

Step-by-step explanation:

It is given that sin3a= cos(a-20)

Both are acute angles

cos ( 90-3a) = cos ( a-20)

[sin theta =cos(90-theta)]

So,

90-3a=a-20

90+20=a+3a

110=4a

a= 110/4

a= 27.5


rubidheena03: but the answer is 23degree
rubidheena03: plz give me the crt answer
gargnakul67: How
rubidheena03: i don't know
rubidheena03: they gave me the ans alone not the steps
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