if sin3a=cos(a-20),where 3a and (a-20) are both acute angles,then find a=?
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Answered by
0
Answer:
Step-by-step explanation:
cos(90-3a)=cos(a-20)
90+20=a+3a
110=4a
a=27.75
I think its this
rubidheena03:
how do i know
Answered by
1
Answer:
Step-by-step explanation:
It is given that sin3a= cos(a-20)
Both are acute angles
cos ( 90-3a) = cos ( a-20)
[sin theta =cos(90-theta)]
So,
90-3a=a-20
90+20=a+3a
110=4a
a= 110/4
a= 27.5
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