If sin3A=cos(A-26°). find the value of A
Answers
Answered by
18
sin3A = cos (A- 26)
sin 3A = sin (90-A+ 26)
Now, 3A = 116 - A
4A = 116
A = 29
Hope this wil help u
sin 3A = sin (90-A+ 26)
Now, 3A = 116 - A
4A = 116
A = 29
Hope this wil help u
Answered by
5
SIN3A=COS(A-26)
SIN3A=SIN(90-A+26)
3A=116 -A
4A=116
A=29.
IS IT CORRECT ...!!!!
SIN3A=SIN(90-A+26)
3A=116 -A
4A=116
A=29.
IS IT CORRECT ...!!!!
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