Question

if sin3A=cos(A-26°) ,wher3A is an acute angle , of a A

Answer 1

sin 3A = cos( A - 26° )

From the identities of trigonometry, we know that sin( 90 - ∅ ) = cos ∅. Therefore, cos( A - 26° ) will be sin( 90 - { A - 26° } ).

sin 3A = sin{ 90 - ( A - 26° ) }

As both the values are represented in terms of sin, they are equal.

3A = 90 - ( A - 26° )

3A = 90 - A + 26°

3A + A = 90 + 26

4A = 116

A =$\dfrac{116 \degree}{4}$

A = 29 °

Therefore the value of angle A is 29°.

Answer 2

Answer:

29

Step-by-step explanation:

i hope you understand