Question

If sin3A = cos(A – 26°), where 3A is an acute angle, find the value of A.​

Answer 1

Answer:

A = 29°

Step-by-step explanation:

Given- sin 3A = cos( A-26° )

[ We know sin∅ = Cos ( 90° - ∅ ).]

So, Cos( 90°-3A) = Cos( A-26°)

Comparing both angles

( 90°-3A) = ( A-26°)

90°-3A = A-26°

Take constant terms one side and variable terms other side

90°+26° = A+3A ( when we take no. to other side symbols changes)

116° = 4A

$\frac{116}{4} = A$

$A = 29°$

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