If sin3a =cos(a-26°) where 3a is an acute angle,find the value of a.
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sin3a=cos(a-26)
sin3a=cos(90-(a-26)) (sin a=cos(90-a))
sin3a=sin(90-a+26)
sin3a=sin(116-a)
3a=116-a (Taking the angles common as sin is common)
4a=116
a=116/4
a=29
Therefore your answer is 29 degrees
:)
taruntambrahalli:
Hope you understood the method
Burlungboro
Answered by
0
Answer: 29
Step-by-step explanation:
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