Question

If sin3A=cos(A-36), where 3A is an acute angle, find the value of A

Answer 1

Answer:sin3A= cos(90-36)

A=54

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

Sin 3a= cos(a-36)

Cos a (90° - 3a) = cos a(a-36)

90-3a=a-36

-3a-a= 36-90

-4a = -54

A= -54/-4