Question

if sin3A+cos2B=2, then cos2A+sin3B =?

Answer 1

Answer:

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Step-by-step explanation:

Given relation,

sin3A+cos2B=2

We know the maximum value of sin3A=1 and cos2B=1 . This can only satisfy the given relation.

Hence sin3A=1=sin90 => A=30 Again cos2B=1=cos0 =>B=0 So we get cos2A+sin3B =cos(2×30)+sin(3×0) =co60=1/2