If sin⁴A + sin² = 1
then tan⁴ + tan² = ?
Tawhid2002:
the answer will be 1
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Answered by
3
Sin⁴A + sin²A = 1
sin⁴A = 1 - sin²A
sin⁴A = cos²A ------1)
now .. from ... question ..
tan⁴A + tan²A
sin⁴A/cos⁴A + sin²A/cos²A
cos²A /cos⁴A + sin²A/sin⁴A---------from 1
1/cos²A + 1/sin²A
sin²A+cos²A/cos²A ×sin²A
=> 1/cos²A×sin²A
=> sec²A ×cosec²A
sin⁴A = 1 - sin²A
sin⁴A = cos²A ------1)
now .. from ... question ..
tan⁴A + tan²A
sin⁴A/cos⁴A + sin²A/cos²A
cos²A /cos⁴A + sin²A/sin⁴A---------from 1
1/cos²A + 1/sin²A
sin²A+cos²A/cos²A ×sin²A
=> 1/cos²A×sin²A
=> sec²A ×cosec²A
Answered by
0
cosec^6 A is an answer.
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