if sin5a =cos a where 5a and 4a are acute angle find the value of a
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sin5a=cos4a
sin5a=sin(90°-4a)
5a=90°-4a
5a+4a=90°
9a=90°
a=10°
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sin5a=sin(90°-4a)
5a=90°-4a
5a+4a=90°
9a=90°
a=10°
plz mark it as brainliest...
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