If Sin5a=Cos4A . Find 2 Sin3A -√3 tan 3A.
Answers
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1
Step-by-step explanation:
=
(cos5A+cosA)+(cos4A+cos2A)
(sin5A+sinA)+(sin4A+sin2A)
we know that sinC+sinD=2sin
2
C+D
cos
2
C−D
sinC−sinD=2cos
2
C+D
sin
2
C−D
=
2cos3Acos2A+2cos3AcosA
2sin3Acos2A+2sin3AcosA
=
2cos3A(cos2A+cosA)
2sin3A(cos2A+cosA)
=tan3A=tanxA
⇒x=3
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