Question

If sin7x=cos 11x, then the value of
tan9x+cot9x:​

Answer 1

Answer:

sin/cos=11/7=tan

11/7×9+7/11×9=

1530/77...

Answer 2

Answer:

=tan²9x/tan9x+1/tan9x

=(tan²9x+1)÷tan9x

=sec²9x÷tan9x

=(1/cos²9x)×(cos9x/sin9x)

( cutting of cos9x )

=1/cos9x.sin9x

=sec9x.cosec9x