Question

if sinA=1÷√2 &cotB=1.PTsin(A+B)=1

Answer 1

Sin A= 1/√2
we know,
Sin 45°= 1/√2
Therefore, A=45° ...(1)
Cot B= 1
We know,
Cot 45°= 1
So,
B= 45°...(2)
From 1 & 2,
(A+B) = (45°+45°)
= 90°
We know,
Sin 90°= 1
Hence, proved

Hope this will help...