If SinA= 1/✓2 and sinB=1/✓3 than prove that tan1/2(A+B)*cot1/2(A-B) = 5+2√6. Can anyone help me answering this?
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first you find value of A and B from sin A and sin B...put the value of tan A-B and Cot A+B...A = π/4 or 45 degree and B = π/6or 30 ....
if not then convert tan into sin/cos or cot = cos /sin.... and break by using trigonometry identity
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