if SinA=1/2, CosB=1/2, findA,B and Sin2A.
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2
1) sin A = sin30 degree
A =30 degree
2) cos B=cos 60 degree
B = 60 degree
3) sin 2A
sin 2×30
sin 60 answer
A =30 degree
2) cos B=cos 60 degree
B = 60 degree
3) sin 2A
sin 2×30
sin 60 answer
Answered by
1
sinA=1/2
sin30=1/2
Therefore, A=30
cosB=1/2
cos60=1/2
Therefore,B=60
sin 2A=sin2×30
sin60=root3/2
sin30=1/2
Therefore, A=30
cosB=1/2
cos60=1/2
Therefore,B=60
sin 2A=sin2×30
sin60=root3/2
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