if sinA=1÷2,find sin2A
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Answered by
18
sin 2A = 2sinAcosA,
sinA = 1/2,
Cos A = √(1-sin²A),
=> CosA = √(1-1/4)
=> Cos A = √(3/4) = √3 /2
=> Sin 2A = 2*(1/2)*(√3/2)
=> Sin 2A = √3 / 2,
I have done like this because we don't know where the angle A lies in whether 1st quadrant or second, So I have done like this,
If you need easiest answer then ,
Sin 30° = 1/2 = Sin A,
=> A = 30°,
now sin 2A = sin 60° = √3/2,
So the answer to your question is √3/2,
Hope you understand !!
Have a good day !
sinA = 1/2,
Cos A = √(1-sin²A),
=> CosA = √(1-1/4)
=> Cos A = √(3/4) = √3 /2
=> Sin 2A = 2*(1/2)*(√3/2)
=> Sin 2A = √3 / 2,
I have done like this because we don't know where the angle A lies in whether 1st quadrant or second, So I have done like this,
If you need easiest answer then ,
Sin 30° = 1/2 = Sin A,
=> A = 30°,
now sin 2A = sin 60° = √3/2,
So the answer to your question is √3/2,
Hope you understand !!
Have a good day !
bhai97:
thanks
Answered by
4
SaichandraarshExpert
Hey guy here is ur answer :-__________________________________________________________
Sin a=1/2
That means the a is a angle
a =sin inverse(1/2)
Therefore the value of a=30°
We have to find value of sin2a
Sin 2a=sin 2(30°)
Sin 2a=sin 60°
Therefore the value of sin2a=√3/2
I hope it helps u if u r satisfied plz mark as brainlist
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