Question

If sinA=1/2, find the value of 2secA / 1+tan^2 A

Answer 1

This is the solution of your question.

Answer 2

since, sinA = 1/2

then cosA = √(1 - sin^2 A )

cosA = √1 - (1/2)^2

cosA = √(1 - 1/4 )

cosA = √3 /2

secA = 1/ cosA = 1/(√3/2 ) = 2/ √3

secA = 2/√3

tanA = sinA / cosA = ( 1/2 )/ (√3 / 2 )

TanA = 1/2 × 2/√3

TanA = 1/√3

therefore ,

2secA /1 + tan^2 A

=(2 × 2/√3 ) / 1 + (1/√3 )^2

=(4 /√3 ) / (1 + 1 /3 )

=(4 /√3 ) / ( 4 /3 )

=4 /√3 × 3/ 4

=3 / √3

=3 /√3 × √3 /√3

=3√3 / 3

=√3
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Your Answer : √3
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