Math, asked by hv7005920, 1 year ago

If sinA =1//2 find the value of 2secA/1+TAN^2A

Answers

Answered by Allsha
2
sin A = 1/2
cos A = √3 / 2
Tan A = 1/3 
√3

sec A = 1/cos A
sec A = 1 / 
√3/2 
sec A = 2/3 √3

2sec A / 1 + tan 
² A
= 2 (2/3) √3 / 1 + (1/√3)²
= 4√3 /3    /   1 + 1 / 3
= 4√3 / 2
Answered by rrrrrrr3
7
hope it WILl help you
Attachments:

hv7005920: HOW DID 3/ROOT3 BECOME 3 ROOT 3/3
rrrrrrr3: by rationalizing
hv7005920: THANKS FOR HELP
rrrrrrr3: welcome
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