Question

If sinA =1//2 find the value of 2secA/1+TAN^2A

Answer 1

sin A = 1/2
cos A = √3 / 2
Tan A = 1/3 √3

sec A = 1/cos A
sec A = 1 / √3/2 
sec A = 2/3 √3

2sec A / 1 + tan ² A
= 2 (2/3) √3 / 1 + (1/√3)²
= 4√3 /3    /   1 + 1 / 3
= 4√3 / 2

Answer 2

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