Question

If sinA=1/2, then the value of CotA=?

Answer 1

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$\huge\tt\red{\bold{\underline{\underline{❥Question᎓}}}}$If sinA=1/2 ,then find the value of CotA=?

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$⟹SinA= \frac{1(P)}{2(H)}$

Here perpendicular is 1 & Hypotenuse is 2

$\red{By. using. Pythagoras. theorem }$:-

$⟹{H}^{2} = {P}^{2} + {B}^{2}$

$⟹ {(2)}^{2} = {1}^{2} + {B}^{2}$

$⟹4 - 1 = {B}^{2}$

$⟹ {B}^{2} = 3$

$⟹B = \sqrt{3}$

Now CotA=Base/Perpendicular

$⟹CotA= \frac{ \sqrt{3} }{1} = \sqrt{3}$

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Answer 2

Answer:

sinA=1/2 = a/h

by phthagoras theorem

b= √3

putting cotA=b/p

=> cotA = √3/1