Question

If sinA = 1/3 evaluate cosA×cosecA+tanA×secA

Answer 1

Step-by-step explanation:

sinA= 1/3 = p/h

Now,

h^2 = p^2 + b^2

b^2 = h^2 - p^2

b^2 = 3^2 - 1^2

b^2 = 9 - 1

b^2 = 8

b = 2√2

now,

cosA × cosecA + tanA× secA

= 2√2/3 × 3 + 1/2√2 × 3/2√2

= 2√2 + 3/8

= 16√2 + 3 / 8