Question

If sinA=1/3, evaluate cosA cosecA + tanA secA.​

Answer 1

Answer:

sin a = 1/3

BC / AC = 1/3

BC = 1

AC = 3

by Pythagoras property,

(AC)² (AB)² + (BC)²

[3]² = (AB)² + (1)²

(AB)² = 9-1

= 8

cos A cosecA + tanA secA = 2√2/3*3+1/2√2*3/2√2.

=16√2 + 3/8