Question

If sinA =1/3 , evaluate cosA cosecA+tanA secA.

Answer 1

just use Pythagoras theorem to find the other side , given sin a=1/3 =opposite /hypotenuse

now find all other trigonometric functions needed

Answer 2

Step-by-step explanation:

sin A =1/3

sin A = p/h=1/3

So, p=1 and h=3

Hence,b=√8 [ By Pythagoras theorem]

cos A = b/h =√8/3

cosec A= h/p=3/1=3

tan A = p/b=1/√8

sec A = h/b =3/√8

Since,

cos A. cosec A + tan A. sec A

=√8/3×3/1+1/√8×3/√8

= (8√8+3)/8