if sinA = 1/3 find cosA
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2√2/3 is the ans............
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Hello.....Mate...
Ur answer is....
sinA = opposite side/hypotenuse
= 1/3
cosA = adjacent side/hypotenuse
By Pythagoras theorem
1×1 + (X)raise to 2 = 3×3
1 + (X) = 9
(X) = 9-1 = 8
cosA = 8/ 3
I hope you understand..........
aman240292:
really?
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