Question

If sinA=1/3 show that cosA cosecA+tanAsecA=16_/root-2+3/8

Answer 1

Answer:

2√2 + 3/8

Note : Please check the question or correct the answer

Step-by-step explanation:

given sin A =  1/3  (which is opp/hyp )

by pythagorous theorem, adj = √(3²-1²) = √8 = 2√2

=> cos A = adj/hyp = (2√2) / 3 ;

    tan A = opp/adn = 1 / (2√2) ;

    cosec A = 1/sin A = 3;   sec A = 1/cos A = 3 /(2√2)

So, cosA cosecA+tanAsecA

= [ (2√2) / 3] [3]  +  [1 / (2√2)] [3 /(2√2)]

= 2√2 + 3/8