Question

If sinA=1/3, then find cosA​

Answer 1

Step-by-step explanation:

given,sinA=1/3

sinA=opposite to A/hypotenus

let k be the common factor

(H)²=(S)²+(S)²

(3K)²=K²+S²

9K²=K²+S²

S²=9K²+K²

S²=10k²

S=√10k

cosA=adjacent to A/hypotenus

=√10k/3k

=√10/3