Question

If sinA=1/3 then find CosA CosecA+tanA secA​

Answer 1

AnswEr:-

We know,

• Sin = Perpendicular/Hypotenuse = 1/3

So , Perpendicular = 1 and Hypotenuse = 3.

→ H² = B² + P²

=> 3² = B² + 1²

=> √8 or 2√2 = B

And we know,

• Cosec θ= 1/Sin θ

• Sec θ = 1/Cos θ

• Tan θ= Sin θ/Cos θ

• Cos θ= Base/Hypotenuse

→ Cos A = 2√2/3

→ Sec A = 3/2√2

→ Cosec A = 3

→ Tan A = 1/2√2

→ Cos A Cosec A + Tan A Sec A

→ 2√2/3 × 3 + (1/2√2 × 3/2√2)

→ 2√2 + 3/8

→ (16√2 + 3)/8

Hence, (16√2 + 3)/8

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