Question

if sinA=1/3evaluate cosA,cosecA+tanA,secA​

Answer 1

Trignometric Ratios

→ Sin = Perpendicular/Hypotenuse = 1/3

Hence, Perpendicular = 1 and Hypotenuse = 3.

→ H² = B² + P²

→ 3² = B² + 1²

→ √8 or 2√2 = B

Cosec ∅ = 1/Sin ∅

Sec ∅ = 1/Cos ∅

Tan ∅ = Sin/Cos ∅

Cos ∅ = Base/Hypotenuse

→ Cos A = 2√2/3

→ Sec A = 3/2√2

→ Cosec A = 3

→ Tan A = 1/2√2

[By filling respective values]

→ Cos A Cosec A + Tan A Sec A

→ 2√2/3 × 3 + (1/2√2 × 3/2√2)

→ 2√2 + 3/8

→ (16√2 + 3)/8

Answer : (16√2 + 3)/8