if sinA= 1÷3x and tanA=x÷3 then find value of x^2-1÷x^2
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x² - 1/x² = 1/9 If sinA =1/3x and tanA=x/3
Step-by-step explanation:
SinA = 1/3x
TanA = x/3
CosA = SinA/TanA
=> CosA = (1/3x)/(x/3)
=> CosA = 1/x²
=> x² = 1/CosA
x² - 1/x²
= 1/CosA - CosA
= (1 - Cos²A)/CosA
= Sin²A/CosA
= SinA. TanA
= (1/3x) * (x/3)
= 1/9
x² - 1/x² = 1/9
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