Question

if sina=1/root 2 and tanb=1,find the value of sin(a+b), where a and b both re acute

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Answer 1

Step-by-step explanation:

Angle are acute

SinA=1/√2

=sin45°

A=45°

CotB=1

=cot45°

B=45°

Sin(A+B)=sin(45°+45°)

=sin90°

=1

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Answer 2

Answer:

Hey mate here is your answer!

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Sina=1/√2,

Sin 45°=1/√2,

So,A=45°,

Tan B=1,

Tan 45°=1,

So,B=45°.

Now you got the value of A and B so substitute the values in:

Sin(A+B),

Sin(45°+45°),

Sin 90°,

And as you know the value of Sin 90° is 1.

So,1 is the answer.✔✔✔✔✔✔

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