Question

if sinA =1 then value of cos A is ? ??
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Answer 1

Sin A = 1 = P/H

=> H^2 = P^2 + B^2

=> 1 = 1 + B^2

=> B = 0

Base value can't be zero.

Hence , there's an error in the Question. ( By Pythagoras rule )

But ....

Sin A = 1

So, A = π/2 =90°

=> Cos A = Cos π/2 = 0

Answer 2

Step-by-step explanation:

sin + 1 - sin^2 = 1

So, sin - sin^2 =0

sinA ( 1 - sinA) = 0

So, either sinA = 0 or sinA = 1

i.e. A = 0° or A = 90°

For A = 0°

sin0 + cos0 = 0 + 1 = 1

For A = 90°

sin90 + cos90 = 1 + 0 = 1

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