Question

If sinA=12/13 then find secA-tanA/cosA+cotA​

Answer 1

Step-by-step explanation:

sinA = 12/13 = p/h

p= 12units

h= 13units

by pythagoras theorem

b^2= h^2-p^2

b^2= 13^2-12^2

= 169 -144

= 25

b =root of 25

b = 5

secA = 13/5

tanA= 12/5

cosA=5/13

cotA= 5/12

secA-tanA/cosA+cotA

=13/5-12/5 / 5/13+5/12

=1/5 / 60/156 +65/156

=1/5 / 125/156

= 156/625