If sinA 12/13 then tanA
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Answer:
sin A=12/13
cos A=√(1-sin^2A)
=√(1-12^2/13^2)
=√(1-144/169(
=√(169-144)/169
=√(25/169)
=5/13
tan A=sinA/cosA
=12/13/5/13
=12×13/13×5
=12/5
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