Question

If sinA=12/37 find cosA and tanA​

Answer 1

Answer:

CosA=35/37

Tan=12/35

Step-by-step explanation

P = Perpendicular

B = Base

H = Hypotenuse

SinA=P/H=12/37

37^2 - 12^2 = B^2

B^2 = 1225

B = 35

CosA=B/H=35/37

TanA=P/B=12/35

Answer 2

Sin A = 12 /37

We know Sin A = P / H

➡ P/H = 12/37

P = 12k and H = 37k { where k is a constant }

Using Pythagoras theorem

H² = B² + P²

( 37k )² = B² + ( 12k )²

B² = 1369k² – 144k²

B² = 1225 k²

B = √1225k²

B = k√1225

B = 35k

now, Cos A = B / H

= 35k / 37k

= 35 / 37

Tan A = P / B

= 12k / 35k

= 12 / 35

Hope the solution is clear to you!!