Question

if sinA 16/17 find cosA and tanA​

Answer 1

Step-by-step explanation:

sinA = 16/17

We already know that,

Sin^2 A + Cos^2 A = 1

Cos^2 A = 1- Sin^2 A

= 1- 256/289

= 33/289

Cos A = √ 33 /17

Tan A = SinA/ CosA

= 16/17 / √33/17

= 16/√33

Hope it helps you buddy

Answer 2

Answer:

Here is your answer:

Cos A = ( rt 33 ) / 17

Tan A = (16 rt 33 ) / 17

Step-by-step explanation:

Sin A = Perpendicular / Hypotenuse

Cos A = Base / Hypotenuse

Tan A = Sin A / Cos A

Perpendicular = 16 K

Hypotenuse = 17 K

By Pythagoras Theorem,

(Hypotenuse) sq = (Perpendicular) sq + (Base) sq

Therefore Base = sqrt ( 289 K sq - 256 K sq ) =K rt 33

Cos A = (rt 33)/17

Tan A = 16 / ( rt 33 )

Rationalising (16 rt 33 )/ 33

PLZ MARK MY ANSWER AS BRAINLIEST