Math, asked by dipakde2851, 8 months ago

if sinA=2/3 then find cos3A=?

Answers

Answered by Anonymous

Answer:

$\sqrt{5}$

Step-by-step explanation:

sin = opp side/hypotenuse

cos= adj side /hypotenuse

sin =2/3

3 is hypotenuse

3^2=2^2+x^2

x^2=5

x= $\sqrt{5}$

cos= $\sqrt{5}$ /3

cos3A= $\sqrt{5}$ /3*3

cos3A= $\sqrt{5}$

Answered by adityachoudhary2956

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sin = opp side/hypotenuse

cos= adj side /hypotenuse

sin =2/3

3 is hypotenuse

3^2=2^2+x^2

x^2=5

x=√5

cos=√5/3

cos3A= √5/3*3

cos3A= √5

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if sinA=2/3 then find cos3A=?​

Answers

sin = opp side/hypotenuse

cos= adj side /hypotenuse

sin =2/3

3 is hypotenuse

3^2=2^2+x^2

x^2=5

x=√5

cos=√5/3

cos3A= √5/3*3

cos3A= √5

if sinA=2/3 then find cos3A=?