Question

If sinA=2/3 then find the value of cosA/tanA+cotA.Iif anybody answer this,I will mark it as brainliest answer​

Answer 1

Answer:

hello mate..

Step-by-step explanation:

If sinA, cosA and tanA are in GP, then

CosA/SinA = tanA/cosA

Cos^2A = tanA.sinA (Cross-multiplying)

Cos^3A = sin^2A

(Simplifying using tanA = sinA/cosA)------------(1)

CosA/SinA = tanA/cosA (Given)

CotA = 1/cotA .1/cosA

Cot^2A = 1/cosA = secA (Cross-multiplying)-------(2)

Then, cot^6A = sec^3A (On cubing both sides of 2)----------(3)

Now, equation(3) -equation(2)

= cot^6A - cot^2A

= sec^3A - secA

=secA(sec^2A - 1) [taking secA common term outside]

=secA.tan^2A [from

Identity sec^2A - tan^2A = 1]

=1/cosA . Sin^2A/cos^2A

=sin^2A/cos^3A..............4

Substituting 1 in 4

We know, sin^2A = cos^3A

Cot^6A - Cot^2A = 1

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Answer 2

Answer:

Step-by-step explanation:

Plz see the attachment