Question

if SINA = 2/5 , find the value of 5+ 4 cot square A?​

Answer 1

Answer:

26

Step-by-step explanation:

SinA=P/H and CotA=B/P

Given that SinA=2/5 = P/H

Let P=2x and H=5x then

by Pythagoras

P^2+B^2=H^2

Putting the values of P and H we get B=√21x

then we will put the values in the given question

5 + 4Cot^2A

=5+ 4(√21x/2x)^2

=5+4*(21/4)

=5+21

=26

Hope you got your answer!