Question

if sinA+2 cosA=1, show that 2sinA-cosA=2​

Answer 1

Step-by-step explanation:

Hope it will help you

thanks

Answer 2

Answer:

$\sin(a) + 2 \cos(a) = 1 \\ \sin(a) - 1 = 2\cos(a) \\ \frac{\sin(a) - 1}{2} = \cos(a) \: \: \: \: \: \: ......(1)\\ Now, \\ \\ 2 \sin(a) - \cos(a) = 2 \\ 2 \sin(a) - \frac{\sin(a) - 1}{2} = 2 \\ \frac{2 \sin(a) - \sin(a) + 1}{2} = 2 \\ 3 \sin(a) + 1 = 4 \\ 3 \sin(a) = 3 \\ \sin(a) = \frac{3}{3} = 1 \\ 1 + 2 \cos(a) = 1 \\ 2 \cos(a) = 0 \\ \cos(a) = 0 \\ \\ So, \\ 2 \sin(a) - \cos(a) = 2 \\ 2 \times 1 - 0 = 2 \\ 2 = 2 \\ \\ here \\ \: LHS = RHS$