Math, asked by mrx69877, 2 months ago

if sinA= 2mn/m^2+n^2 find value of sinAcotA/cosA

Answers

Answered by shreya5859

0

Answer:

sinA=2mn/(m²+n²)

cot = sinA cotA ÷ cos A=cos÷sin

(sinA*cotA)/cosA=1

LHS

(sinA*cosA/sinA)cosA

= 1

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