Math, asked by roshanmishra722, 9 months ago

If sinA= √3/2 and cosB= ½, then A/B=?

Answers

Answered by dhairyamharidwar
0

 \sin(a)  =  \frac{ \sqrt{3} }{2}

 \sin(a)  =  \sin(60)

a = 60

 \cos(b)  =  \frac{1}{2}

 \cos(b)  =  \cos(60)

b = 60

 \frac{a}{b}  =  \frac{60}{60}  = 1

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Answered by piyushikumari2004
2

Answer:

sinA= √3/2

cosB= ½

Therefore Angle A = 60° [Sin 60°= √3/2]

& Angle B = 60° [ Cos 60° = 1/2]

now A/B = 60/60 = 1

Answer is 1

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