Question

if sinA=√3/2 and sinB=1 find sin(B-A)​

Answer 1

Answer:

A = 60, B = 90

Step-by-step explanation:

sin ( 90-60) = sin 30 = 1/2

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Answer 2

Step-by-step explanation:

Here in the ∆ ABC , a=2 , b=3 , sinA =2/3 , < B =? We know from properties of triangle ,

a/sinA = b/sinB =c/sinC { c/sinC is not relevant here} => a/sinA =b/sinB => 2/(2/3) = 3/sinB

=>6/2 =3/sinB => 3 = 3/sinB => sinB = 3/3,

=> SinB = 1= sin90° => B = 90°