If sinA=√3/2andtanB=√3,prove that cos(A-B)=1 ,where A and B both are acute angle
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Answer:
Step-by-step explanation:
sinA=√3/2 (Given)
∴A=60
Also, tanB=√3
∴B=60
∴cos (A-B)=cos0
=1
HENCE PROVED
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