Question

If sinA=3/4 and cosB=-12/13 where A and B both lies in second quadrant, then find the value of sin (A+B)​

Answer 1

Answer:

-18/13

Step-by-step explanation:

sin(A+B)= sinA cosB+ cosA sinB

= (3/4 ) (-12/13)+ (-12/13) (3/4)

= -9/13 - 9/13

= -18/13